derivative of 1/y

Sep 2009
230
7
ok so i have the problem:

If
and
, find
by implicit differentiation.

so i differentiate both sides and get -1/x^2 + -y'/y^2 = 0

then i solve for y' and get y'=-y^2/x^2

this is wrong but i do not know where i went wrong..... im thinking it has to do with the derivative of the 1/y.

could i get some advice please =)

thank you
 

skeeter

MHF Helper
Jun 2008
16,217
6,765
North Texas
ok so i have the problem:

If
and
, find
by implicit differentiation.

so i differentiate both sides and get -1/x^2 + -y'/y^2 = 0

then i solve for y' and get y'=-y^2/x^2

this is wrong but i do not know where i went wrong..... im thinking it has to do with the derivative of the 1/y.

could i get some advice please =)

thank you
why do you say that \(\displaystyle y' = -\frac{y^2}{x^2}\) is wrong?

it's not.
 
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Reactions: mybrohshi5
Sep 2009
230
7
you are right, it is right lol. i just must have not used enough decimal places in my answer because my web homework was saying it was incorrect but i just put it in again with a few more decimal places and it is right now =)

thanks for clarifying this for me