d(x/lnx) /dx

Dec 2008
5
0
Hi can anyone help please.

Use standard results about differentiation to find f'(x) where f(x) = x / lnx
 
Feb 2010
1,036
386
Dirty South
Hi can anyone help please.

Use standard results about differentiation to find f'(x) where f(x) = x / lnx
You should know what quotient rule is! Try applying that rule.
 
Jun 2010
54
0
Skopje
solved

here is the result - 1/lnx-1/lnx^2

to get the result use the rule : (u'v-uv')/v^2 where in this case u is x and v is lnx,this derivative is simple gl (Wink)
 
May 2010
1,260
410
Mauritius
here is the result - 1/lnx-1/lnx^2

to get the result use the rule : (u'v-uv')/v^2 where in this case u is x and v is lnx,this derivative is simple gl (Wink)
I'd like to know the answer too, but is the answer you just gave correct?

I mean, is \(\displaystyle ln x^2 = (ln x)^2\)

Using the quotient rule, I know that I get:

\(\displaystyle \frac{ln x - 1}{(ln x)^2}\)

:confused: