So for a point(0,0,0) and a unit vector (-.0088, .0030, -.9999) the equation would be:

-.0088(x-0) + .003(y-0) -.9999(z-0) = 0

-.0088x + .003y -.9999z = 0

In order to find the angles of the plane I tried calculating the angle between two planes. My thought was the axes unit vectors would be:

(1,0,0) for x

(0,1,0) for y

(0,0,1) for z

And their equations of a plane with the same point (0,0,0):

x=0

y=0

z=0

Using the equation:

cos α = __|A1·A2 + B1·B2 + C1·C2|__

√A1² + B1² + C1² √A2² + B2² + C2²

The results seem wrong so I believe I'm on the wrong track.