Okay so I am totally confused on how to do this prroblem it asking to condense the following problem:

3log_4a+5log_4b-log_4c

please help(Crying)

Log questions are pre-calc not trig (Hi)

Either way use the power law and the addition/subtraction laws.

Power Law: \(\displaystyle k\log_b(a) = \log_b(a^k)\)

Addition Law: \(\displaystyle \log_b(a) + \log_b(c) = \log_b(ac)\)

Subtraction Law: \(\displaystyle \log_b(a) - \log_b(c) = \log_b \left(\frac{a}{c}\right)\)

For example \(\displaystyle \log_2(3) + 3\log_2(6) = \log_2(648)\)

(\(\displaystyle 648 = 6^3 \times 2\) in case you were wondering)