Hi,
P(z)=\(\displaystyle z^6-2z^3cos(3\alpha)+1\)
How to show that the solutions of P(z) are: \(\displaystyle a_k=e^{i(-\alpha+\frac{2k\pi}{3}}\) and \(\displaystyle b_k=e^{i(+\alpha+\frac{2k\pi}{3}}\)????
P(z)=\(\displaystyle z^6-2z^3cos(3\alpha)+1\)
How to show that the solutions of P(z) are: \(\displaystyle a_k=e^{i(-\alpha+\frac{2k\pi}{3}}\) and \(\displaystyle b_k=e^{i(+\alpha+\frac{2k\pi}{3}}\)????