A adam_leeds Oct 2008 393 10 May 31, 2010 #1 How do you complete the square of \(\displaystyle (-2y^2 +2yz -z^2)/2\) into the form \(\displaystyle -(a((x-b)^2))/2\) Thanks Adam Last edited: Jun 1, 2010
How do you complete the square of \(\displaystyle (-2y^2 +2yz -z^2)/2\) into the form \(\displaystyle -(a((x-b)^2))/2\) Thanks Adam
skeeter MHF Helper Jun 2008 16,217 6,765 North Texas May 31, 2010 #2 adam_leeds said: How do you complete the square of \(\displaystyle (-2y^2 +2yz -z^2)/2\) Thanks Adam Click to expand... \(\displaystyle \frac{-2y^2 + 2yz - z^2}{2}\) \(\displaystyle -\frac{y^2 + y^2 - 2yz + z^2}{2}\) \(\displaystyle -\frac{y^2 + (y-z)^2}{2}\) ... that's about all i could do with it. Reactions: adam_leeds
adam_leeds said: How do you complete the square of \(\displaystyle (-2y^2 +2yz -z^2)/2\) Thanks Adam Click to expand... \(\displaystyle \frac{-2y^2 + 2yz - z^2}{2}\) \(\displaystyle -\frac{y^2 + y^2 - 2yz + z^2}{2}\) \(\displaystyle -\frac{y^2 + (y-z)^2}{2}\) ... that's about all i could do with it.
mr fantastic MHF Hall of Fame Dec 2007 16,948 6,768 Zeitgeist Jul 3, 2010 #5 adam_leeds said: How do you complete the square of \(\displaystyle (-2y^2 +2yz -z^2)/2\) into the form \(\displaystyle -(a((x-b)^2))/2\) Thanks Adam Click to expand... It cannot be put into that form. (By the way, what is x meant to be? The variables of your problem are y and z).
adam_leeds said: How do you complete the square of \(\displaystyle (-2y^2 +2yz -z^2)/2\) into the form \(\displaystyle -(a((x-b)^2))/2\) Thanks Adam Click to expand... It cannot be put into that form. (By the way, what is x meant to be? The variables of your problem are y and z).