I have a standard deck of 52 cards. How do I find the number of hands of 13 cards that contain 4 cards of the same rank? (A,2-10, J,Q,K)
I'm starting off with (48 choose 9) but I am unsure of how to account for the multiples that have been calculated (the Inclusion, Exclusion principles)
Very stuck on this, please help!
I'm starting off with (48 choose 9) but I am unsure of how to account for the multiples that have been calculated (the Inclusion, Exclusion principles)
Very stuck on this, please help!