a.) If she wants 3 boys and 3 girls on the committee, how many options does she have?

b.) If Tom and Howard, two of the 13 boys, are not speaking and will not work together, how many options for workable committees does Ms. Ruiz have?

I am pretty sure about part a being 13C3 * 12C3 = 62,920 workable comm.

Part b is what is throwing me. I am pretty sure the way to do it would be 62,920 - committees with Tom and Howard together, but I dont know how to figure that number out