2^2 x 2^3
= 2^2+3
= 2^5
= 32

#### skeeter

MHF Helper
You check it ...

what is the value of $2^2$?

... of $2^3$?

multiply the the two values ... is the product the same as your result?

#### yeongil

2^2 x 2^3
= 2^2+3
= 2^5
= 32
I know you don't mean this, but what I highlighted looks like $$\displaystyle 2^{2}+3$$. You obviously mean $$\displaystyle 2^{2+3}$$. To indicate that without LaTeX, use grouping symbols:
2^(2+3)

#### HallsofIvy

MHF Helper
And, of course, 2^2= 4 while 2^3= 8 so (2^2)(2^3)= (4)(8)= 32. More generally, yes, (a^m)(a^n)= a^(m+ n). That's one of the "laws of exponents". The other is (a^m)^n= a^(mn).

#### rahuljoshi

please write your question using latex or using parenthesis for better understanding.
(2^2)*(2^3)
here two exponents with same base are multiplied and when the base is same,we add the powers.
So (2^2)*(2^3)=2^(2+3)=2^5=32.
$a^n×a^m=a^{n+m}$
Here, $2^2×2^3= 2^{2+3}$
$2^5=32$