# Bits of Computer Memory

#### harpazo

How many bits of computer memory will be required to store the integer x, where x = -sqrt{810,000}, if each digit requires 4 bits of memory and the sign of x requires 1 bit?

I decided to simply the radical. This led to x = -900. Of course, this makes no sense. What exactly is this question asking?

#### HallsofIvy

MHF Helper
Why would $$\displaystyle -\sqrt{810,000}= -900$$ "make no sense"? The problem is asking you how many bits would be required to save "-900" in memory if "each digit requires 4 bit of memory and the sign requires 1 bit". 900 has 3 digits so that would require 3*4= 12 bits and the additional one bit for the sign brings it to 13 bits.

(9, decimal, is 1001, binary, so using the bit 1 for negative, the 13 bits would be 1 1001 0000 0000.)

• 1 person

#### harpazo

Why would $$\displaystyle -\sqrt{810,000}= -900$$ "make no sense"? The problem is asking you how many bits would be required to save "-900" in memory if "each digit requires 4 bit of memory and the sign requires 1 bit". 900 has 3 digits so that would require 3*4= 12 bits and the additional one bit for the sign brings it to 13 bits.

(9, decimal, is 1001, binary, so using the bit 1 for negative, the 13 bits would be 1 1001 0000 0000.)
This problem has to do with the binary system that I never learned back in my school days.