Hi all,
\(\displaystyle \angle OAP = 90^{\circ}\), tangent is perpendicular to radius at point of contact
\(\displaystyle \angle OAB = \frac{180152}{2}=14^{\circ}\), angle sum of triangle is 180, triangle OAB is isosceles (equal angles opposite equal sides)
\(\displaystyle \angle PAB = 90 14 = 76^{\circ}\)
\(\displaystyle \angle PBA = 180  71  76 = 33^{\circ}\), angle sum triangle is 180
BUT....
Angle sum of quadrilateral is \(\displaystyle 360^{\circ}\)
In which case
\(\displaystyle \angle PBA = 360 152  90  71 = 47^{\circ}\)
(Punch)
is this a poorly drawn up question or is the reasoning flawed?
thanks.
\(\displaystyle \angle OAP = 90^{\circ}\), tangent is perpendicular to radius at point of contact
\(\displaystyle \angle OAB = \frac{180152}{2}=14^{\circ}\), angle sum of triangle is 180, triangle OAB is isosceles (equal angles opposite equal sides)
\(\displaystyle \angle PAB = 90 14 = 76^{\circ}\)
\(\displaystyle \angle PBA = 180  71  76 = 33^{\circ}\), angle sum triangle is 180
BUT....
Angle sum of quadrilateral is \(\displaystyle 360^{\circ}\)
In which case
\(\displaystyle \angle PBA = 360 152  90  71 = 47^{\circ}\)
(Punch)
is this a poorly drawn up question or is the reasoning flawed?
thanks.
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