Arithmetic Progression

Nov 2015
100
1
Kolkata, India
If 5 AMs are inserted between 3 and 13/2, then find the third AM. How will I solve it? It seems to be quite easy but I can't solve it.
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
AM is "arithmetic mean"? But don't know what you mean by 5 of them being inserted between two given numbers. I would be inclined, given no other information, to pick 5 numbers equally spaced between3 and 13/2. That would give 6 equally long intervals between 3 and 13/2 so the length of each interval would be (13/2- 3)/6= 7/12. The third point would be at 3+ 3(7/12)= 3+ 7/4= 12/4+ 7/4= 19/4= 4 and 3/4.

Again, that is my interpretation of what appears to me to be an ambiguous question.
 
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Nov 2015
100
1
Kolkata, India
Then the question is incorrect. The answers are 7/12, 11/4, 15/12 and 19/4. Now you might find out the wrong part in he question by seeing the answers.