T Tessarina Feb 2009 63 0 May 26, 2010 #1 a rhombus has an area of 50 cm^2 and an internal angle of size 63 degrees. Find the lenth of its sides. please show all working out.

a rhombus has an area of 50 cm^2 and an internal angle of size 63 degrees. Find the lenth of its sides. please show all working out.

skeeter MHF Helper Jun 2008 16,216 6,764 North Texas May 26, 2010 #2 Tessarina said: a rhombus has an area of 50 cm^2 and an internal angle of size 63 degrees. Find the lenth of its sides. please show all working out. Click to expand... ... use the parallelogram area formula provided in your previous post.

Tessarina said: a rhombus has an area of 50 cm^2 and an internal angle of size 63 degrees. Find the lenth of its sides. please show all working out. Click to expand... ... use the parallelogram area formula provided in your previous post.

T Tessarina Feb 2009 63 0 May 26, 2010 #3 i worked out the other one, but with this one i just can't seem to get the right answer. i think iam doing something wrong,

i worked out the other one, but with this one i just can't seem to get the right answer. i think iam doing something wrong,

skeeter MHF Helper Jun 2008 16,216 6,764 North Texas May 26, 2010 #4 Tessarina said: i worked out the other one, but with this one i just can't seem to get the right answer. i think iam doing something wrong, Click to expand... can't fix it if we don't know what you tried ...

Tessarina said: i worked out the other one, but with this one i just can't seem to get the right answer. i think iam doing something wrong, Click to expand... can't fix it if we don't know what you tried ...

Prove It MHF Helper Aug 2008 12,883 4,999 May 27, 2010 #6 Try using the formula \(\displaystyle A = ab\sin{\theta}\). Like Skeeter said, show us what working you have done. We are not here to do your work for you.

Try using the formula \(\displaystyle A = ab\sin{\theta}\). Like Skeeter said, show us what working you have done. We are not here to do your work for you.

T Tessarina Feb 2009 63 0 May 27, 2010 #7 this is the working out i did: A= 50cm^2 1/2 x a x c x sin63= 50 acsin63= 100 -and thats all i got to.

this is the working out i did: A= 50cm^2 1/2 x a x c x sin63= 50 acsin63= 100 -and thats all i got to.

Prove It MHF Helper Aug 2008 12,883 4,999 May 27, 2010 #8 Tessarina said: this is the working out i did: A= 50cm^2 1/2 x a x c x sin63= 50 acsin63= 100 -and thats all i got to. Click to expand... You're almost there. Just remember that in a rhombus, all sides are equal.

Tessarina said: this is the working out i did: A= 50cm^2 1/2 x a x c x sin63= 50 acsin63= 100 -and thats all i got to. Click to expand... You're almost there. Just remember that in a rhombus, all sides are equal.

T Tessarina Feb 2009 63 0 May 27, 2010 #9 then do i work it out by going-- 2asin63=100 2a=100/sin63 2a=112.23 a=56.11 but then if i double that to get the area of the whole rhombus i get 112.23 which is the wrong answer. the answer is: 137.0cm^2 what am i doing wrong?

then do i work it out by going-- 2asin63=100 2a=100/sin63 2a=112.23 a=56.11 but then if i double that to get the area of the whole rhombus i get 112.23 which is the wrong answer. the answer is: 137.0cm^2 what am i doing wrong?

Prove It MHF Helper Aug 2008 12,883 4,999 May 27, 2010 #10 Tessarina said: then do i work it out by going-- 2asin63=100 2a=100/sin63 2a=112.23 a=56.11 but then if i double that to get the area of the whole rhombus i get 112.23 which is the wrong answer. the answer is: 137.0cm^2 what am i doing wrong? Click to expand... It should actually be \(\displaystyle a^2\sin{\theta} = 100\). BTW you only halve when you are finding the area of a triangle. Since it's half of a parallelogram.

Tessarina said: then do i work it out by going-- 2asin63=100 2a=100/sin63 2a=112.23 a=56.11 but then if i double that to get the area of the whole rhombus i get 112.23 which is the wrong answer. the answer is: 137.0cm^2 what am i doing wrong? Click to expand... It should actually be \(\displaystyle a^2\sin{\theta} = 100\). BTW you only halve when you are finding the area of a triangle. Since it's half of a parallelogram.