P Padma May 2010 2 0 May 28, 2010 #1 Hi all, i am not able to get the relation between area and circumference in the given below.could any one please help me out If the circumference of a circle is decreased by 50% then the percentage of decrease in its area is? Regards Padma

Hi all, i am not able to get the relation between area and circumference in the given below.could any one please help me out If the circumference of a circle is decreased by 50% then the percentage of decrease in its area is? Regards Padma

1 1337h4x Apr 2009 96 0 May 28, 2010 #2 Circumference = 2*pi*r which can be rewritten as r= C/(2*pi) Area = pi*(r^2) substitute with 50% of C pi * ((1/2)(1/(2*pi))^2 What is your coefficient ?

Circumference = 2*pi*r which can be rewritten as r= C/(2*pi) Area = pi*(r^2) substitute with 50% of C pi * ((1/2)(1/(2*pi))^2 What is your coefficient ?

Prove It MHF Helper Aug 2008 12,883 4,999 May 28, 2010 #3 Padma said: Hi all, i am not able to get the relation between area and circumference in the given below.could any one please help me out If the circumference of a circle is decreased by 50% then the percentage of decrease in its area is? Regards Padma Click to expand... If you magnify the length of a shape by a scale factor \(\displaystyle k\), then the area is magnified by \(\displaystyle k^2\). In this case, the length scale factor \(\displaystyle k = \frac{1}{2}\). So what is the area scale factor? Reactions: mr fantastic

Padma said: Hi all, i am not able to get the relation between area and circumference in the given below.could any one please help me out If the circumference of a circle is decreased by 50% then the percentage of decrease in its area is? Regards Padma Click to expand... If you magnify the length of a shape by a scale factor \(\displaystyle k\), then the area is magnified by \(\displaystyle k^2\). In this case, the length scale factor \(\displaystyle k = \frac{1}{2}\). So what is the area scale factor?