Applying the Laws of Sines or Cosines

Apr 2013
8
0
United States
Solve the triangle.

B = 36°, a = 41, c = 17

choices are

b ≈ 29, C ≈ 20, A ≈ 124
b ≈ 44, C ≈ 20, A ≈ 124
b ≈ 29, C ≈ 121, A ≈ 23
b ≈ 44, C ≈ 24, A ≈ 120
 
Apr 2013
39
13
Maitland, NSW, Australia
These look like test questions..

So all I will put is this:

\(\displaystyle b^2 = a^2 + c^2 - 2acCos(B)\)

Where angle B is opposite side b
 
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