Applications

May 2010
6
0
A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 0.5 meters, its length is 4 meters, and its top is 3 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8 m/s**2.)

Could you guys show me how to do this?
 

may

May 2010
13
0
maybe the solution is like this:
first find the vol of the cylinder use this formula
Volumecylinder = pi r2 h
=pi(0.5)2 (4)
=3.141592


then use density=mass×volume to find the mass
673=m
×3.141592
m=214.22kg

F=ma
=
214.22kg×9.8
=2099.38

use 9.8 as a because of the force of gravitation

work done =force
×displacement
=2099.38
×3