Suppose the pilot instead had managed to get the airplane engine started such that he was able to apply full throttle and the airplane climbed along a straight line angled above the horizontal so that it gained altitude at a steady rate of 4.61 m/s. Assuming he was again flying with an airspeed of 131 km/h.

**Determine the flight angle above the horizontal the plane is flying.**

My attempt: if we draw a triangle, its hypotenuse is the thrust force, its opposite side is the force of gravity. So to find the angle we have to use this

\(\displaystyle sin \theta = \frac{mg}{F_{thrust}}\)

\(\displaystyle \theta = sin^{-1}\frac{12753}{4.07}\)

But I can't evaluate \(\displaystyle sin^{-1} 3133.4\). The correct answer has to be

**7.28°**. Can anyone help?