R r-soy Oct 2009 290 0 May 30, 2010 #1 A particle is moving with a velocity of 60.0 m/s in positive x direction at t= 0 and t = 15.0 s the velcity decreases uniformly to zero . What was the acceleration during this 15.0-s interval ? what is the significance of the sign of your answer ? my answer is Vo = 0 a = 60 - 0 / 15 = 4

A particle is moving with a velocity of 60.0 m/s in positive x direction at t= 0 and t = 15.0 s the velcity decreases uniformly to zero . What was the acceleration during this 15.0-s interval ? what is the significance of the sign of your answer ? my answer is Vo = 0 a = 60 - 0 / 15 = 4

Unknown008 May 2010 1,260 410 Mauritius May 30, 2010 #2 Actually, the particle has a negative acceleration, and hence, you should do (0-60)/15 = -4 m/s^2