B bwong890 Jun 2010 3 0 Jun 7, 2010 #1 thanks tonio and skeeter for helping me with the other problem. heres more problems i need help with T.T Find derivative of: y = cos^-1(x+y) y = tan^-1(x+y) Find Integrals of: (sec(x)^4)/(sqrt(tanx)) dx

thanks tonio and skeeter for helping me with the other problem. heres more problems i need help with T.T Find derivative of: y = cos^-1(x+y) y = tan^-1(x+y) Find Integrals of: (sec(x)^4)/(sqrt(tanx)) dx

mr fantastic MHF Hall of Fame Dec 2007 16,948 6,768 Zeitgeist Jun 7, 2010 #2 bwong890 said: thanks tonio and skeeter for helping me with the other problem. heres more problems i need help with T.T Find derivative of: y = cos^-1(x+y) y = tan^-1(x+y) [snip] Click to expand... Re-write as x = cos(y) - y and x = tan(y) - y and find dx/dy in the usual way. Then dy/dx = 1/(dx/dy). bwong890 said: [snip] Find Integrals of: (sec(x)^4)/(sqrt(tanx)) dx Click to expand... Substitute \(\displaystyle \sec^4 (x) = \sec^2 x \sec^2 x = (1 + \tan^2 x) \sec^2 x\) and then make the substitution \(\displaystyle u = \tan x\). If you need more help, please show all your work and say where you get stuck.

bwong890 said: thanks tonio and skeeter for helping me with the other problem. heres more problems i need help with T.T Find derivative of: y = cos^-1(x+y) y = tan^-1(x+y) [snip] Click to expand... Re-write as x = cos(y) - y and x = tan(y) - y and find dx/dy in the usual way. Then dy/dx = 1/(dx/dy). bwong890 said: [snip] Find Integrals of: (sec(x)^4)/(sqrt(tanx)) dx Click to expand... Substitute \(\displaystyle \sec^4 (x) = \sec^2 x \sec^2 x = (1 + \tan^2 x) \sec^2 x\) and then make the substitution \(\displaystyle u = \tan x\). If you need more help, please show all your work and say where you get stuck.