5/m - 1/2

Jul 2010
8
0
Is it just 5/m - 1/2 because it cant be simplified any further?
 
Aug 2009
35
5
Philippines
You have to clarify what you are asking. Using parentheses would really help.

Do you mean you want to do \(\displaystyle \frac{5}{m} - \frac{1}{2}\)?

In which case, you can take the least common denominator which is \(\displaystyle 2m\) and proceed like you are doing ordinary fractions.
 
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Jul 2010
8
0
This confuses me because if 2m is the l.c.d. then wouldn't it be something like....

10/2m - 1m/2m?

Or is it...

10/2m - 1/2m?

Or is it...

10/2m - 1/2? But m isnt on both sides here?
 
Aug 2009
35
5
Philippines
Actually, to answer your original question, there isn't anything more we can do to \(\displaystyle \frac{5}{m} - \frac{1}{2}\) to simplify it. We can only do the operation, which is subtraction. If you use 2m as the least common denominator, you'll get \(\displaystyle \frac{5}{m} - \frac{1}{2} = \frac{{10 - m}}{{2m}}
\). And that's pretty much it. (Nod)