Find all pairs of positive integers x and y that safisfy the equation: 1/x - 1/y = 1/2005

phgao May 2005 39 0 May 4, 2005 #1 Find all pairs of positive integers x and y that safisfy the equation: 1/x - 1/y = 1/2005

phgao May 2005 39 0 Jul 13, 2005 #4 Hi there, i was wondering how you rearrange my first equation: Namely: 1/x - 1/y = 1/2005 Into: y = -2005 + (2005^2/2005-x) Thanks!

Hi there, i was wondering how you rearrange my first equation: Namely: 1/x - 1/y = 1/2005 Into: y = -2005 + (2005^2/2005-x) Thanks!

phgao May 2005 39 0 Jul 13, 2005 #5 Ok solved. No need to post an answer. To solve add and subtract 2005^2 from the numerator... then it falls in place. Thanks anyway.

Ok solved. No need to post an answer. To solve add and subtract 2005^2 from the numerator... then it falls in place. Thanks anyway.

S SbD Sep 5, 2005 #6 how can you prove it tho? how do you work it out? x, y 1604, 8020 1980, 158796 2000, 802000 2004, 4018020 ??

how can you prove it tho? how do you work it out? x, y 1604, 8020 1980, 158796 2000, 802000 2004, 4018020 ??

A ardnas Aug 2005 24 0 Sep 10, 2005 #7 Into: y = -2005 + (2005^2/2005-x) Why is it like that? Why isn't it y= -2005 + (2005^2/x-2005)