t12and0

  1. S

    Intergral at a point sint+t t=12&0.

    Hi, Trying to work this one out, \int_0^{12} (\sin{t} + {t}), dx The answer shows = (72 - cos12) - (0-1) =(73-.84) =72.16 I calculate (72-.98) - (0-1) which equals 70.02. Anyone willing to have a quick look and try and see where I went...