Given this circuit...
Circuit values are also given...
I'm trying to determine the total power absorbed by the elements and the total power delivered by the elements.
My understanding is that p = iv is used for elements that ARE passive (current i leaves the negative terminal of the element)...
What is the use of calculus in computer engineering.
we study math in computer like boolean algebra,general math for programming but what computer does with calculus?(Clapping)
Hi all,
I am trying to understand the implications of taking the integral of different metrics/measurements, specifically energy and volumes. Here's my current understanding as it relates to energy:
Energy = power * time. For example, kWh = kW * h.
If you take the integral of power over a...
Hello, I am studying for a midterm this week. One of the practice problems is to find the radius of convergence of \sum_{n=0}^{\infty} a_n x^n where a_n = 5^n if n is odd and a_n = 1/3^n if n is even. It took me a while to hazard a guess that I take the smaller of the two radii? Then a =...
Hi,
I am looking for an example of two power series with different radii of convergece,R1 and R2 ,that a linear combination of the two series has a strictly larger radius of convergence than min{R1,R2}.
Thank's in advance
Sorry if the image is not very clear (please tell me if it is illegible).
Part a) and b) are quite straight forward. Part c)i) I did using part b) from the fact that any real number to the power of an even integer is positive.
Part ii) was a little bit harder. My working out is shown below...
Hi
I hope someone can help me with this question here.
I would like to do a power analysis for sample size, but I am unsure how to approach it because I am measuring heterogeneity in my dataset.
Here are the details:
I have two different types of cell lines and I am measuring the growth of...
for d/dx(e^x) , the series should be start from 2 rather than 1 , right ? because when k = 1 , the circled part would become 0 , the series for (e^x) is 1 + x + ..........
As the title says, I'm having a lot of trouble finding a power series representation of a function. Here it is:
And here's my attempt at a solution:
I had a lot of trouble trying to reindex the summations such that I'd have a single summation at the end. This is what I ultimately got...
Just wanted to make sure I'm doing this correctly:
y = 5(x + 3)^2(2x - 1)^5
y' = 5(x + 3)^2[5(2x - 1)^4*2] + (2x - 1)^5[10(x + 3)*1]
-----
y = (2x - 7)^2 / (4x - 1)
y' = {(4x - 1)[2(2x - 7)*2] - (4)(2x - 7)^2} / (4x - 1)^2
This is as far as my professor requires me to go; no combining...
So I went through this problem and I'm not sure if I'm using the wrong formula or something or I made a mistake, but I would love if someone could check my work and tell me what I'm doing wrong
What is the power of the following information given that u = 51.0 with significance level of .05...
Hi I am having difficulty with the following question any idea where I should start i.e. what formula I should use to begin?
The instantaneous power, p, in an electric circuit is given by p = iv, where v is the voltage and i is the current.
Calculate the maximum value of power in the circuit...
Please see the picture I attached.
i want to know how much power (preferably in watts) this will produce. I basically have a giant weight in the air on a beam. This weight drops and truns a pivot, and does so every 30 seconds. if put an alternator on the pivot how many watts would it make? Some...
I've been stuck on a complex analysis problem with showing there is a dense set of singular points for the power series \sum_{n=0}^{\infty} z^{2^n}
I'm guessing I should use the rationals, but I really don't know where to go beyond there. I can parametrize the unit circle with e^{2\pi i\theta}...
suppose I have two power series.
e^x-x=1+\frac{x^2}{2!}+\frac{x^3}{3!}+\frac{x^4}{4!}+ \frac{x^5}{5!}+...
e^{x^2}=1+\frac{x^2}{1}+\frac{x^4}{2!}+\frac{x^6}{3!}+.....
can I say e^{x^2}>e^x-1 because \frac{x^2}{2!}<\frac{x^2}{1} ,\frac{x^3}{3!}<\frac{x^4}{2!} and so on term-by-term....
will this...