p|npn

  1. Singular

    p|((n^p)-n)

    Someone ask me to prove that p|((n^p)-n) for p=prime numbers and n=all integers I don’t know how to write a formal proof. But I know that the problem has 2 condition : Condition 1 p|n^p and p|n so p|((n^p)-n) (if d|a and d|b then d|(a-b) For example 2|((4^2) - 4) Condition 2...