ok, so I have this recurrence:
a(n) = 2(a(n-1)) + 3(a(n-2))
so the degree is k, & k=2, & I used the formula r^2 - 2r - 3, to get the roots r=1 & r= -3.
then I used the general solution technique
a(n) = alpha1(r1^n) + alpha2(r2^n)
& subbed in my "r" values to get:
a(n) = alpha1[(1)^n] +...