# eqthis

1. ### Diff EQ--This is a tough one (for me atleast)

I'm trying to use the variation of parameters method to find the geneneral solution of this equation: y" + 2y' + 2y = 2(e^-x)(tan^2(x)) Here's the work I've done: 1. r^2 + 2r + 2 =0, so by quadratic, r= -1 + i, r=-1 - i 2. yc = c1(e^-x)cos(x) + c2(e^-x)sin(x) 3. yp = f1(e^-x)cos(x) +...