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conjurgates
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complex conjurgates calculus of variations
f(z)=√(|xy| ) |z|=√(x^2+y^2 ) in general Now will that mean f(z)=√((xy)^(1⁄2) )=xy ?? I will appreciate your help, Thanks, Jas
JD007
Thread
Apr 30, 2008
Replies: 1
Forum:
Calculus
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