Solve inR:$\displaystyle \sin x = \sinh (2x - 3) - 1

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- Aug 29th 2009, 12:33 AMdhiabSinh and Sin
**Solve in**R**:**$\displaystyle \sin x = \sinh (2x - 3) - 1

$ - Aug 29th 2009, 01:34 AMred_dog
There is a solution between 2 and 3.

- Aug 29th 2009, 01:54 AMCaptainBlack
- Aug 29th 2009, 06:24 AMpacman
dhiab, we can rewrite it this way,

http://www2.wolframalpha.com/Calcula...image/gif&s=19.

exponentially,

http://www2.wolframalpha.com/Calcula...image/gif&s=19 ,

http://www2.wolframalpha.com/Calcula...image/gif&s=19

by successive approximation, x = 2.18

http://www2.wolframalpha.com/Calcula...image/gif&s=19

dhiab, is this what you need?

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