is this triginometry or algebra?
a rectangle has a length 2√x cm and width √x cm
the length of the diagonal of the triangle is √45 cm
i) find the area of the rectangle
ii) the area of the square is twice the area of the rectangle
find the length of a side of the square.
for part i) i did the a^2 + 0^2 = h^2
then in the calc. i did 2√x got 2√5 then sq it and got 10 ,...then i
did √x got √5 then sq it and got 5 , added them and got 15 so then i did the hypotenuse thing and √45 and got 20, yeah i know you are prob wondering how i got that and to be honest so am i lol because i used a new calc. for this and when i repeated it on an older calc. of mine i got a different answer so the CORRECT answer was :
part 2 was= 6cm, but i got the answer wrong for i) so i was confused