Show for all values of a and b This is what i did : Why the difference in red ? Where did i go wrong ? Thanks for pointing that out .
Last edited by mr fantastic; August 13th 2009 at 03:23 AM. Reason: Fixed latex
Follow Math Help Forum on Facebook and Google+
Hi thereddevils I think you're right and the question is wrong
View Tag Cloud
LinkBack URL
About LinkBacks + \sin^2 (a+2b) = \frac{3}{2}-\frac{1}{2} \cos (2a+2b) (2 {\color{red}\cos b}+1)<br />
)
![<br />
\frac{1}{2} [1 - \cos (2a)] + \frac{1}{2} [1 - \cos (2a+2b)] + \frac{1}{2} [1 - \cos(2a+4b)]<br />](http://latex.codecogs.com/png.latex? <br />
\frac{1}{2} [1 - \cos (2a)] + \frac{1}{2} [1 - \cos (2a+2b)] + \frac{1}{2} [1 - \cos(2a+4b)]<br />
)
