Prove the identity

Printable View

Aug 3rd 2009, 10:10 AM
Yuroichi

Prove the identity

$4sin2xcos2x=2sin4x$

$6cot^22x-csc^22x=6cos^32x$
Aug 3rd 2009, 10:46 AM
e^(i*pi)

Quote:

Originally Posted by Yuroichi

$4sin2xcos2x=2sin4x$

$6cot^22x-csc^22x=6cos^32x$

1. Use the double angle identity $sin(2u) = 2sin(u)cos(u)$ .
In this case $u=2x$

2. This is not an identity - try $x = 1.25\pi$

$\frac{6cos^2(2x)-1}{sin^2(2x)}$

All times are GMT -8. The time now is 08:51 PM.

Copyright © 2005-2017 Math Help Forum. All rights reserved.