Solve for x: (16/81)^(sin^2 x) + (8/9)^(cos^2 x) = 26/27
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Originally Posted by pacman Solve for x: Something wrong here? If you put then . But the function is greater than 1 throughout the interval [0,1], so it can never be equal to 26/27.
ok say instead of 26/27 it was 3/2. how can you solve it for an exact soln? w/o using any approximating methods
Originally Posted by Krahl ok say instead of 26/27 it was 3/2. how can you solve it for an exact soln? w/o using any approximating methods If It is not Sub then It becomes a cubic equation after solving u
i plot this one: y = (16/81)^(sin^2 x) + (8/9)^(cos^2 x) for x =0 to pi radian. In my graph it looks like this, any comments?
and this one, (16/81)^(sin^2 x) + (8/9)^(cos^2 x) = 26/27; what does it mean?
Originally Posted by pacman i plot this one: y = (16/81)^(sin^2 x) + (8/9)^(cos^2 x) for x =0 to pi radian. In my graph it looks like this, any comments? My comment: it is not true that this is the plot of . Rather, this is the plot of . Also: This function assumes a minimum value of at . But it is always .
Originally Posted by pacman and this one, (16/81)^(sin^2 x) + (8/9)^(cos^2 x) = 26/27; what does it mean? It means that this time you have plotted for a larger range of x and, for some reason that I cannot fathom, seem to have surprised yourself with the result.
your observation is quite alright with me, thanks
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