This is a 3D problem. I did one similar to it in this thread:

http://www.mathhelpforum.com/math-he...g-problem.html . But there are some differences.

First you'll need to imagine a bird's eye view of the ground. See attachment #1. You've got a triangle ABT. Remember that bearings are measured with 0° = N. Angle T is 45°, angle A is 70°, and angle B is 65°. Use the Law of sines to find side AT:

$\displaystyle \frac{\sin 45^{\circ}}{270} = \frac{\sin 65^{\circ}}{AT}$

Why AT? Because you need that length to find the height of the tower at T. See attachment #2. (

*Actually, the placement of T here is wrong -- it should be at the base of the tower, not the top. Sorry about that.*) Use the tangent ratio to find AT.

$\displaystyle \tan 34^{\circ} = \frac{h}{AT}$

01

EDIT: Beaten to it by skeeter...