1. ## please check trig work

1. the period of the function $\displaystyle y= cos3x$ in radians is $\displaystyle 3 \pi$

2. the phase shift of the function $\displaystyle y=3sin5( \theta - \frac{\pi}{4})$ is $\displaystyle \frac{\pi}{4}$

3. the vertical shift of the function $\displaystyle y=3tan2(4 \theta - \frac{\pi}{2})+5$ is 5

4. the phase shift of the function $\displaystyle y=5sin(2x+6)-7$ is 7 units left

2. Originally Posted by william

3. the vertical shift of the function $\displaystyle y=3tan2(4 \theta - \frac{\pi}{2})+5$ is 5
I agree, answers to 1,2 and 4 can be found from the thread

http://www.mathhelpforum.com/math-he...rig-work2.html

3. Originally Posted by pickslides
I agree, answers to 1,2 and 4 can be found from the thread

http://www.mathhelpforum.com/math-he...rig-work2.html
thanks, but i'm still unclear on the phase shift because here http://www.mathhelpforum.com/math-he...rig-work2.html in question 2 you stated it is the value of b,the phase shift, and i stated in question 2 here that the phase shift is pi/4?

for 4 it would be 6 units left, right?

and for 1 the period is 2pi/3, right?

thanks

4. Originally Posted by william
thanks, but i'm still unclear on the phase shift because here http://www.mathhelpforum.com/math-he...rig-work2.html in question 2 you stated it is the value of b,the phase shift, and i stated in question 2 here that the phase shift is pi/4?
b and $\displaystyle \frac{\pi}{4}$ are in the same place in there respective equations so they mean the same thing.

Originally Posted by william

for 4 it would be 6 units left, right?
It is left

Originally Posted by william

and for 1 the period is 2pi/3, right?

thanks
Yeppers