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Math Help - What would these functions look like?

  1. #1
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    What would these functions look like?

    y=sin6x
    and
    y=sin1/4x

    In other words what might the zeroes be?
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  2. #2
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    Quote Originally Posted by crosser43 View Post
    y=sin6x
    and
    y=sin1/4x

    In other words what might the zeroes be?
    As masters wrote in this thread (http://www.mathhelpforum.com/math-he...lp-answer.html) the b is important. For the 1st one, b = 6, and for the 2nd one, b = 1/4.
    (BTW, your 2nd one in ambiguous. Some people may think that you mean y = \sin \frac{1}{4x} instead of y = \sin \frac{1}{4}x.)

    You have to remember the zeros for y = sin x, which is
    0,\; \pi,\; 2\pi,\; 3\pi,...;
    in other words, multiples of \pi.

    So to find the zeros of y = sin bx, divide the zeros I listed above by b. For y = sin 6x, the zeros are
    0,\; \frac{\pi}{6}\; \frac{\pi}{3}\; \frac{\pi}{2},....

    I'll let you try the other one.


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  3. #3
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    Quote Originally Posted by crosser43 View Post
    y=sin6x
    and
    y=sin1/4x

    In other words what might the zeroes be?
    Let u = 6x . So now we have y=\sin{u} . For which values of u does y=\sin{u} = 0 ?

    Now use this and the fact that x = \frac{u}{6} to find out the zeroes to y=\sin{6x}


    EDIT: tooo slow
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