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Thread: Help with answer?

  1. #1
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    Help with answer?

    $\displaystyle y=sin2x$

    1)What does the 2 indicate?

    2) Is the period $\displaystyle \pi$?

    3) Where are its zeroes?
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  2. #2
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    Quote Originally Posted by crosser43 View Post
    $\displaystyle y=sin2x$

    1)What does the 2 indicate?

    2) Is the period $\displaystyle \pi$?

    3) Where are its zeroes?
    Hi crosser43,

    In $\displaystyle y=\sin bx$, b indicates the period of the sine curve.

    In $\displaystyle y=\sin 2x$, the period is 2.

    The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is $\displaystyle 2\pi$. So, a coefficient of b=1 is equivalent to a period of $\displaystyle 2\pi$.

    To get the period of the sine curve for any coefficient b, just divide $\displaystyle 2\pi$ by the coefficient b to get the new period of the curve.

    So, the period of $\displaystyle y=\sin 2x$ is $\displaystyle \frac{2\pi}{2}=\pi$


    The coefficient b and the period of the sine curve have an inverse relationship, so as b gets smaller, the length of one cycle of the curve gets bigger. Likewise, as you increase b, the period will decrease.

    The zeros of the curve in the interval $\displaystyle 0 \le x \le 2\pi$ are $\displaystyle \{0, \frac{\pi}{2}, \pi , \frac{3\pi}{2}, 2\pi\}$.

    Just click on the attachments. They should clear up (I hope).
    Attached Thumbnails Attached Thumbnails Help with answer?-picture-period-sinx.gif   Help with answer?-diagram-graph-period-sin2x.gif  
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