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Math Help - Another trig equation question

  1. #1
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    Another trig equation question

    Let's continue
    sin(2x-\frac{\pi}{6})+4sinx+1=0
    Last edited by mp3qz; July 22nd 2009 at 05:53 AM.
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  2. #2
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    Start by using the sine of a difference formula:
    \sin (u - v) = \sin u \cos v - \cos u \sin v.


    01
    Last edited by mr fantastic; July 22nd 2009 at 05:00 AM.
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  3. #3
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    If you can, why don't you solve?
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  4. #4
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    Quote Originally Posted by mp3qz View Post
    If you can, why don't you solve?
    THis is MathHelpForum, not MathSolvetheproblemcompletelyForum.

    You've been given a suggestion. Have you tried it? How far did you get? Where are you stuck?
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  5. #5
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    sorry, that's my teacher's test.

    i can't solve, and this is solution


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  6. #6
    MHF Contributor red_dog's Avatar
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    It's something wrong in the second equation. Where is 4\sin x?
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  7. #7
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    sorry, it's wrong.
    sorry every body. But who can help me this equation? PLEASE
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