# Math Help - Solving trig equation

1. ## Solving trig equation

1]Show that 2[sinxcosx - 1/2 ] = sin2x -1

2] Hence, determine the general solution for:

2[sinxcosx - 1/2 ] =0

2. $2(sinxcosx-\frac{1}{2}) = 2sinxcosx-2*\frac{1}{2} = 2sinxcosx-1$ We know that $sin2x=2sinxcosx$ so we have
$2sinxcosx-1 = sin2x-1$

3. thanks alot!