Results 1 to 3 of 3

Thread: Solving trig equation

  1. July 20th 2009, 08:29 AM #1
    Viky
    Viky is offline
    Newbie Viky's Avatar
    Joined
    Mar 2009
    From
    Chatsworth, South Africa
    Posts
    10

    Exclamation Solving trig equation

    1]Show that 2[sinxcosx - 1/2 ] = sin2x -1

    2] Hence, determine the general solution for:

    2[sinxcosx - 1/2 ] =0
    Follow Math Help Forum on Facebook and Google+
  2. July 20th 2009, 08:49 AM #2
    SENTINEL4
    SENTINEL4 is offline
    Member SENTINEL4's Avatar
    Joined
    Mar 2009
    From
    Kastoria, Greece
    Posts
    92
    2(sinxcosx-\frac{1}{2}) = 2sinxcosx-2*\frac{1}{2} = 2sinxcosx-1 We know that sin2x=2sinxcosx so we have
    2sinxcosx-1 = sin2x-1
    Follow Math Help Forum on Facebook and Google+
  3. July 20th 2009, 08:54 AM #3
    Viky
    Viky is offline
    Newbie Viky's Avatar
    Joined
    Mar 2009
    From
    Chatsworth, South Africa
    Posts
    10
    thanks alot!
    Follow Math Help Forum on Facebook and Google+
« solving trig equation | need help with homework »

Similar Math Help Forum Discussions

  1. Trig word problem - solving a trig equation.
    Posted in the Trigonometry Forum
    Replies: 6
    Last Post: March 14th 2011, 08:07 AM
  2. Solving a trig equation #2
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: February 16th 2011, 04:59 PM
  3. solving a trig equation
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: February 16th 2011, 01:29 PM
  4. Solving A Trig Equation
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: January 30th 2010, 01:02 PM
  5. Solving trig equation...
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: December 1st 2009, 06:43 AM

Search Tags


/mathhelpforum @mathhelpforum