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Thread: Solving trig equation

  1. Jul 20th 2009, 07:29 AM #1
    Viky
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    Exclamation Solving trig equation

    1]Show that 2[sinxcosx - 1/2 ] = sin2x -1

    2] Hence, determine the general solution for:

    2[sinxcosx - 1/2 ] =0
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  2. Jul 20th 2009, 07:49 AM #2
    SENTINEL4
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    2(sinxcosx-\frac{1}{2}) = 2sinxcosx-2*\frac{1}{2} = 2sinxcosx-1 We know that sin2x=2sinxcosx so we have
    2sinxcosx-1 = sin2x-1
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  3. Jul 20th 2009, 07:54 AM #3
    Viky
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    thanks alot!
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