Solving trig equation

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July 20th 2009, 07:29 AM
Viky

Solving trig equation

1]Show that 2[sinxcosx - 1/2 ] = sin2x -1

2] Hence, determine the general solution for:

2[sinxcosx - 1/2 ] =0(Headbang)
July 20th 2009, 07:49 AM
SENTINEL4

$2(sinxcosx-\frac{1}{2}) = 2sinxcosx-2*\frac{1}{2} = 2sinxcosx-1$ We know that $sin2x=2sinxcosx$ so we have
$2sinxcosx-1 = sin2x-1$
July 20th 2009, 07:54 AM
Viky

thanks alot!

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