# Solving trig equation

• July 20th 2009, 08:29 AM
Viky
Solving trig equation
1]Show that 2[sinxcosx - 1/2 ] = sin2x -1

2] Hence, determine the general solution for:

$2(sinxcosx-\frac{1}{2}) = 2sinxcosx-2*\frac{1}{2} = 2sinxcosx-1$ We know that $sin2x=2sinxcosx$ so we have
$2sinxcosx-1 = sin2x-1$