(a-b)/(a+b)=[tan{(A-B)}/2]/[tan{(A+B)}/2]
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Hello matsci0000 Originally Posted by matsci0000 (a-b)/(a+b)=[tan{(A-B)}/2]/[tan{(A+B)}/2] You don't say so, but I presume that are sides and angles in a triangle. In which case, using the Sine Rule: Now use the identities and : Grandad
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