of a ABC triangle
a=5 , b=4 and cos(A-B)=31/32
show that c=6
Hello, stud_02!
I found a solution . . . but there must be a better way!
In
Show that: .Code:C * *| * * | * b=4 * | * a=5 * |y * * | * * | * * | * A * - - - * - - - - - - - * B : x D c-x : : - - - - - c - - - - - :
In right triangle .[1]
In right triangle .[2]
Equate [1] and [2]: . .[3]
Substitute into [1]: . .[4]
We are given: .
. . . .
Substitute [3] and [4]: .
. . which simplifies to: .