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Thread: trigonometry

  1. July 12th 2009, 07:25 AM #1
    Rose Wanjohi
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    trigonometry

    prove that tan(90-beta)=cot beta
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  2. July 12th 2009, 07:33 AM #2
    red_dog
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    \tan(90-\beta)=\frac{\sin(90-\beta}{\cos(90-\beta)}=\frac{\sin 90\cos\beta-\sin\beta\cos 90}{\cos 90\cos\beta+\sin 90\sin\beta}=\frac{\cos\beta}{\sin\beta}=\cot\beta
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