find the solution for the equation tanA=3sinA for values of A in the range -180 <= A <= 180 (deg evidently)

so i used tanA= sinA/cosA which gives cosA = sinA/3sinA = 1/3. anything wrong up until here?

my calculator says cos^-1 1/3 = 70.5 deg, so my answer is +- 70.5 deg.

however the answer includes +-180° as well. is this even possible? who is wrong?