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Math Help - Trig Problem

  1. #1
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    Trig Problem

    I am doing a section on trigonometric functions of any angle and I have no idea how to do the folowing problem can someone help me out?


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  2. #2
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    You should be able to draw two "special" triangles and label their sides. These are the 30-60-90 triangle and the 45-45-90 triangle. (See Special right triangles - Wikipedia, the free encyclopedia for diagrams.) Note that
    \frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}} and
    {\sqrt{2}} = \frac{\sqrt{2}}{1}.


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  3. #3
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    So for part (a) the measure of the triangles sides would be 1, 2, and radical 3?
    Like this:


    And because COT is hypotenuse (radical 3) over opposite (1) the angle would be 30 ?
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  4. #4
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    No, that's not right. Cotangent is adjacent of opposite. Furthermore, for the 30-60-90 triangle, the hypotenuse is 2, not \sqrt{3}. Can you try again?


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  5. #5
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    So for adjacent of opposite being 1/ . That would make the 1 adjacent and the the opposite? Which would make it for 60?
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  6. #6
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    Yes. Now do the similar with part (b).


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