I am doing a section on trigonometric functions of any angle and I have no idea how to do the folowing problem can someone help me out?
You should be able to draw two "special" triangles and label their sides. These are the 30°-60°-90° triangle and the 45°-45°-90° triangle. (See Special right triangles - Wikipedia, the free encyclopedia for diagrams.) Note that
$\displaystyle \frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}$ and
$\displaystyle {\sqrt{2}} = \frac{\sqrt{2}}{1}$.
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