TRIANGLE: http://img172.imageshack.us/img172/1344/trig.jpg

I worked out that it would be 127 cm2

Printable View

- Jul 6th 2009, 12:37 AMolivia59Is this the correct area of this triangle?
TRIANGLE: http://img172.imageshack.us/img172/1344/trig.jpg

I worked out that it would be 127 cm2 - Jul 6th 2009, 12:41 AMProve It
- Jul 6th 2009, 12:43 AMolivia59
But i thought the rule was 1/2 * bc sin A

- Jul 6th 2009, 12:46 AMProve It
That's exactly the same rule. I've just chosen two different sides of the triangle.

Point is, you need two sides of the triangle and the angle between them.

BTW I always like to keep the solutions exact where possible, hence the square root value rather than the decimal. - Jul 6th 2009, 12:49 AMolivia59
ok, but when i enter 1/2 * 12 * 30 * sin 45 on the calculator it gives me 127....is that not right? i dont understand where you get the 90 from?

- Jul 6th 2009, 12:51 AMyeongil
I'm not sure why you reposted this question when I already answered it in your other thread: http://www.mathhelpforum.com/math-he...-triangle.html. Did you not see it? :confused:

01 - Jul 6th 2009, 12:51 AMProve It
Like I said, I've kept the answer exact.

The answer is not .

The answer is .

Notice that when you put it into the calculator you get a decimal answer. This is NOT exact, it is a decimal approximation to .

You have done the right thing but have gotten the decimal answer rather than the exact answer. - Jul 6th 2009, 12:53 AMyeongil
- Jul 6th 2009, 12:56 AMolivia59
oh i see now, thanks for your help.

(not sure how to reply on forums, havent really used them before, dont know whether im sposed to click post reply or quote) - Jul 6th 2009, 01:06 AMProve It