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Math Help - How to work out the angle between a Rope anchor system

  1. #1
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    How to work out the angle between a Rope anchor system

    Hello everyone,
    Just wondering how I work out the angle on a Artificial High Directional.
    In the photo, the angle I want to work out is between the metal Gin Pole and one of the tie downs connecting it to the hand rail, lets say the Yellow one on the front / right.
    I'm trying to figure this out with out using a Protractor.
    Can anyone help please?

    Thanks,
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by kiwionarope View Post
    Hello everyone,
    Just wondering how I work out the angle on a Artificial High Directional.
    In the photo, the angle I want to work out is between the metal Gin Pole and one of the tie downs connecting it to the hand rail.
    I'm trying to figure this out with out using a Protractor.
    Can anyone help please?

    Thanks,
    Photos from AMS Training - Work and Rescue | Facebook

    What angle does the gin pole make with the ground? Measure it and I'll solve you're problem. I will give you a general solution if you like.
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  3. #3
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    Hello, thanks for such a fast reply!
    The Gin Pole is 90 degrees, straight up.

    Obviously angles play a massive roll on Rope Rescue so with every system we rig, I need to work out the forces on the system.
    But - want to be able to do this without a protractor.

    Thanks again.
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  4. #4
    No one in Particular VonNemo19's Avatar
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    Detroit, MI
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    Quote Originally Posted by kiwionarope View Post
    Hello, thanks for such a fast reply!
    The Gin Pole is 90 degrees, straight up.

    Obviously angles play a massive roll on Rope Rescue so with every system we rig, I need to work out the forces on the system.
    But - want to be able to do this without a protractor.

    Thanks again.
    If the gin pole is straight up, the solution to the problem you've posted is:

    Let \theta=\text{angle the rope makes with the gin pole}

    Let d=\text{the horizontal distance from where the rope is tied to the rail to the gin pole}

    Let l=\text{the lengthof rope}

    Then \theta=\sin^{-1}\left(\frac{d}{l}\right)

    So, just divide the distance from the knot to the gin pole by the length of the rope and press the \sin^{-1} button onyour calculator.

    REMARK. I understand that you may only have a given length of rope, but need to make a certain angle. In this case, you'll use the same formula, but a little algebra and trig will be necessary to solve for one of the unknowns.

    This will work for any length of rope at any distance from the gin pole, AS LONG AS THE GIN POLE REMAINS VERTICAL.
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