write general solution of sin4x - sin2x = 0 cos3x = cos x sin3x = sin2x ack, i dont realli no wat sin4x or cos3x or sin3x is, or how to get to it, so if anybody could help me, i would greatly appreciate it thanx !
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Originally Posted by iiharthero write general solution of sin4x - sin2x = 0 cos3x = cos x sin3x = sin2x ack, i dont realli no wat sin4x or cos3x or sin3x is, or how to get to it, so if anybody could help me, i would greatly appreciate it thanx ! Use the following: or where n is an integer. or where n is an integer.
Originally Posted by iiharthero write general solution of sin4x - sin2x = 0 either .........(1) or ..............(2) for 1st case, for 2nd case,
Last edited by mr fantastic; Jun 20th 2009 at 04:24 PM. Reason: Fixed a latex tag
Originally Posted by iiharthero cos3x = cos x There is a little-known formula for cos 3x: Here is how it's derived: Back to the problem: Now set each factor equal to 0 and solve for x... 01
Originally Posted by yeongil There is a little-known formula for cos 3x: Here is how it's derived: Back to the problem: Now set each factor equal to 0 and solve for x... 01 The style of question and the fact that the OP states: "ack, i dont realli (sic) no (sic) wat (sic) sin4x or cos3x or sin3x is" suggests that the approach advised in my first post is probably the best one for the OP to use.
Exactly. If is not necessary to change to "sin(x)" and "cos(x)". To solve "sin(3x)= sin(2x)", just write .
Originally Posted by HallsofIvy Exactly. If is not necessary to change to "sin(x)" and "cos(x)". To solve "sin(3x)= sin(2x)", just write and where k is an integer.
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