Originally Posted by

**THSKluv** Write general solutions:

4sinacosa = 1

the answer says (npi)/2 + (-1)^n (pi/12)

except when i did it i got a different answer. if anybody could tell me where i went wrong i would be extremely grateful =D

i rooted both sides : 2sinacosa = 1

therefore, sin2a = 1

2a = (pi n) + (-1) ^n (pi/2)

divide by 2 both sides

a = (pi n)/2 + (-1)^n (pi/4)

Solve for 0 ≤b ≥180

b) secb + tan b = 2cosb

i just realli dont no how to solve this

answer is pi/6 and 5pi/6

any help greatly appreciated ! thankyou !