Originally Posted by
THSKluv Write general solutions:
4sinacosa = 1
the answer says (npi)/2 + (-1)^n (pi/12)
except when i did it i got a different answer. if anybody could tell me where i went wrong i would be extremely grateful =D
i rooted both sides : 2sinacosa = 1
therefore, sin2a = 1
2a = (pi n) + (-1) ^n (pi/2)
divide by 2 both sides
a = (pi n)/2 + (-1)^n (pi/4)
Solve for 0 ≤b ≥180
b) secb + tan b = 2cosb
i just realli dont no how to solve this
answer is pi/6 and 5pi/6
any help greatly appreciated ! thankyou !