1. 112 degrees
2. 252.5 degrees
3. 210 degrees 35'

Convert each radian measure to degrees. Give answers to nearest tenth of a degree.
4. 1.8
5. 3.5
6. 2.41

Find two angles, one positive and one negative that are coterminal with each given angle. If problem is given in p rads give answer in simplified p rads.
7. 980 degrees
8. 240 degrees 25'
9. 4p/3

2. Originally Posted by yoman360
1. 112 degrees
2. 252.5 degrees
3. 210 degrees 35'

Convert each radian measure to degrees. Give answers to nearest tenth of a degree.
4. 1.8
5. 3.5
6. 2.41

Find two angles, one positive and one negative that are coterminal with each given angle. If problem is given in p rads give answer in simplified p rads.
7. 980 degrees
8. 240 degrees 25'
9. 4p/3
1)

$\displaystyle 180^\circ=\pi$ radians

$\displaystyle 1^\circ=\frac{\pi}{180}$ radians

$\displaystyle 112^\circ=\frac{\pi}{180}\cdot112$ radians$\displaystyle =0.622\pi$ radians

You can do the rest..

4)$\displaystyle \pi \mbox{ rad}=180^\circ$

$\displaystyle 1 \mbox{ rad} = \frac {180^\circ} {\pi}$

$\displaystyle 1.8 \mbox{ rad}=\frac {180^\circ} {\pi}\cdot 1.8 \approx (57.2958\times1.8)^\circ \approx 103.13244^\circ$

rest try yourself

3. Originally Posted by yoman360
Find two angles, one positive and one negative that are coterminal with each given angle. If problem is given in p rads give answer in simplified p rads.
7. 980 degrees
8. 240 degrees 25'
9. 4p/3
Coterminal angles differ by multiples of 360° or $\displaystyle 2\pi$, so start adding or subtracting multiples of 360° or $\displaystyle 2\pi$ until you get one positive and one negative. For #7, here is one possible set of answers:

$\displaystyle 980^{\circ} - 360^{\circ} = 620^{\circ}$ and

$\displaystyle 980^{\circ} - (3 \times 360^{\circ}) = 980^{\circ} - 1080^{\circ} = \text{-}100^{\circ}$

You try #8 & 9.

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