I have 2cos^2(x)+cos(x)=1 and I have to solve for x within a standard circle(0-2pi).
Then I have to find the general solution for the above equation and 2tan(x) +SqRt(12)=0(which I previously solved for.
Simply subtract one from both sides and the factor the quadratic
$\displaystyle 2cos^2x+cosx-1=0$
$\displaystyle (2cosx-1)(cosx+1)=0$
now see that cosx=1/2 or -1
what angles do these correspond to?
$\displaystyle 2tanx=-\sqrt{12}$
$\displaystyle 2tanx=-2\sqrt{3}$
$\displaystyle tanx=-\sqrt{3}$
i only know of two angles.......
any questions?
thanx mr. fantastic