I have 2cos^2(x)+cos(x)=1 and I have to solve for x within a standard circle(0-2pi). Then I have to find the general solution for the above equation and 2tan(x) +SqRt(12)=0(which I previously solved for.
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Originally Posted by Blahdkm I have 2cos^2(x)+cos(x)=1 and I have to solve for x within a standard circle(0-2pi). [snip] Simply subtract one from both sides and the factor the quadratic now see that cosx=1/2 or -1 what angles do these correspond to? Originally Posted by Blahdkm [snip] Then I have to find the general solution for the above equation and 2tan(x) +SqRt(12)=0(which I previously solved for. i only know of two angles....... any questions? thanx mr. fantastic
Last edited by VonNemo19; Jun 16th 2009 at 08:22 PM. Reason: Merged posts and some snipping of quote
i only know of two angles....... where n is an integer.
Thank you two SO MUCH for the help! Any chance of assistance finding the general solution of 2cos^2(x) + cos(x)=1?
Originally Posted by Blahdkm Thank you two SO MUCH for the help! Any chance of assistance finding the general solution of 2cos^2(x) + cos(x)=1?
Last edited by alexmahone; Jun 17th 2009 at 04:23 AM.
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